Q44. 44. A question is given followed by two Statements I and
II. Consider the Question and the Statements and mark the correct option. Question: Is (p + q)² - 4pq, where p, q are natural numbers, positive?
Statement I: p < q.
Statement II: p > q.
Which one of the following is correct in respect of the above Question and the Statements?
Detailed Solution
First, simplify the expression: (p + q)² - 4pq = p² + 2pq + q² - 4pq = p² - 2pq + q² = (p - q)² The question asks: Is (p - q)² positive? A square of any real number is always non-negative (≥ 0). It is positive if and only if the base is not zero.
So, (p - q)² is positive if p - q ≠ 0, which means p ≠ q. Statement I: p < q. If p < q, then p ≠ q. Therefore, (p - q)² will be positive. This statement alone is sufficient. Statement II: p > q.
If p > q, then p ≠ q. Therefore, (p - q)² will be positive. This statement alone is sufficient. Since either Statement I alone or Statement II alone is sufficient to answer the question, the correct option is (b).
This question tests basic algebraic identities and properties of numbers, a common element in CSAT.
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