Q69. Consider a 3-digit number.
Question: What is the number?
Statement-1: The sum of the digits of the number is equal to the product of the digits.
Statement-2: The number is divisible by the sum of the digits of the number.
Detailed Solution
We need to find a unique 3-digit number. Statement 1: Sum of digits = Product of digits. For example, if the digits are 1, 2, 3, then 1+2+3=6 and 1*2*3=6. Numbers like 123, 132, 213, 231, 312, 321 all satisfy this.
Since there are multiple possibilities, Statement 1 alone is not sufficient. Statement 2: The number is divisible by the sum of its digits. For example, 102 (sum=3, 102/3=34) and 108 (sum=9, 108/9=12) both satisfy this.
Since there are multiple possibilities, Statement 2 alone is not sufficient. Combining both statements: We look for numbers where the sum of digits equals the product of digits, AND the number is divisible by this sum.
Using the example digits 1, 2, 3 (sum=6, product=6): - 132: Sum=6, Product=6. 132 is divisible by 6 (132/6=22). This number satisfies both. - 312: Sum=6, Product=6. 312 is divisible by 6 (312/6=52).
This number also satisfies both. Since both 132 and 312 satisfy both statements, we cannot determine a unique 3-digit number. Therefore, even using both statements together, the question cannot be answered.
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