- A. The Question can be answered by using one of the Statements alone, but cannot be answered using the other statement alone.
- B. The Question can be answered by using either Statement alone.
- C. The Question can be answered by using both the Statements together, but cannot be answered using either Statement alone.
- D. The Question can be answered even without using any of the Statements.
Answer: D
Explanation
We are given a multiplication puzzle: PP × PQ = RRSS, where P, Q, R, S are distinct non-zero digits, P ≤ 3, and Q ≤ 4.
PP can be written as 11P. PQ can be written as 10P + Q. RRSS can be written as 1100R + 11S = 11(100R + S).
So, 11P × (10P + Q) = 11(100R + S), which simplifies to P × (10P + Q) = 100R + S.
Let’s test possible values for P (1, 2, 3) and Q (1, 2, 3, 4), ensuring P and Q are distinct:
* If P = 1: Q can be 2, 3, 4. The product 11 × (10+Q) would be 11×12=132, 11×13=143, 11×14=154. These are 3-digit numbers, not 4-digit RRSS. So P cannot be 1.
* If P = 2: Q can be 1, 3, 4. The product 22 × (20+Q) would be 22×21=462, 22×23=506, 22×24=528. These are 3-digit numbers, not 4-digit RRSS. So P cannot be 2.
* If P = 3: Q can be 1, 2, 4 (Q cannot be 3 as digits must be distinct).
* If Q = 1: 33 × 31 = 1023. This is not of the form RRSS (e.g., 1122, 2233). Also, P=3, Q=1, R=1, S=2. R=Q, not distinct.
* If Q = 2: 33 × 32 = 1056. Not of the form RRSS.
* If Q = 4: 33 × 34 = 1122. This is of the form RRSS, where R=1 and S=2. Let’s check distinct non-zero digits: P=3, Q=4, R=1, S=2. All are distinct and non-zero. This is a valid solution.
From this, we uniquely determine Q = 4. We found the value of Q without using Statement I or Statement II. Therefore, the question can be answered even without using any of the statements. This is a challenging number puzzle combined with data sufficiency.