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UPSC PREVIOUS-YEAR QUESTIONS

Clocks

Practise the original questions with answers and explanations.

2 questions

Question 12024 · CSAT

37. How many times the hour hand and the minute hand coincide in a clock between 10:00 a.m. and 2.00 p.m. (same day)?
  1. A. 3 times
  2. B. 4 times
  3. C. 5 times
  4. D. 6 times

Answer: A

Explanation

The hour and minute hands coincide 11 times in every 12-hour period (or 22 times in 24 hours). This is because they coincide once every hour, except for the period between 11 and 1 o’clock, where they coincide only once, exactly at 12 o’clock. Let’s count the coincidences in the given time frame: 10:00 a.m. to 2:00 p.m. (a 4-hour period).
1. Between 10:00 a.m. and 11:00 a.m.: The hands coincide once (around 10:55 a.m.).
2. Between 11:00 a.m. and 12:00 p.m.: The hands coincide exactly at 12:00 p.m. (noon).
3. Between 12:00 p.m. and 1:00 p.m.: The hands coincide only at 12:00 p.m., which has already been counted. There is no other coincidence in this hour.
4. Between 1:00 p.m. and 2:00 p.m.: The hands coincide once (around 1:05 p.m.).
Total coincidences = 1 (10-11) + 1 (at 12:00) + 1 (1-2) = 3 times. This question tests knowledge of clock problems, specifically the relative movement and coincidences of the hands.

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Question 22024 · CSAT

40. What is the angle between the minute hand and hour hand when the clock shows 4:25 hours?
  1. A. 12.5°
  2. B. 15°
  3. C. 17.5°
  4. D. 20°

Answer: C

Explanation

To find the angle between the minute hand and hour hand, we can use the formula: Angle = |30H – (11/2)M|, where H is the hour and M is the minutes. Here, H = 4 and M = 25. Angle = |30 × 4 – (11/2) × 25| = |120 – (275/2)| = |120 – 137.5| = |-17.5| = 17.5°. Alternatively, we can calculate the position of each hand from the 12 o’clock mark. The minute hand moves 6° per minute, so at 25 minutes, it is at 25 × 6° = 150°. The hour hand moves 30° per hour and 0.5° per minute. At 4:25, its position is 4 × 30° + 25 × 0.5° = 120° + 12.5° = 132.5°. The angle between the hands is the absolute difference: |150° – 132.5°| = 17.5°. This question tests knowledge of clock problems and angle calculations.

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