- A. 1 and 2 only
- B. 2 and 3 only
- C. 1 and 3 only
- D. 1, 2 and 3
Answer: D
Explanation
Given: p, q are odd integers; r, s are even integers.
1. (p – r)^2 (qs): (odd – even) = odd. So, (p – r)^2 = odd^2 = odd. (q × s) = (odd × even) = even. Therefore, (p – r)^2 (qs) = odd × even = even. Statement 1 is correct.
2. (q – s)q^2 s: (q – s) = (odd – even) = odd. q^2 = odd^2 = odd. s is even. Therefore, (q – s)q^2 s = odd × odd × even = even. Statement 2 is correct.
3. (q + r)^2 (p + s): (q + r) = (odd + even) = odd. So, (q + r)^2 = odd^2 = odd. (p + s) = (odd + even) = odd. Therefore, (q + r)^2 (p + s) = odd × odd = odd. Statement 3 is correct.
All three statements are correct. This question tests basic properties of odd and even numbers (parity) and their behavior under arithmetic operations.