- A. July, May
- B. July, April
- C. June, May
- D. June, April
Answer: B
Explanation
Let’s assign numerical values to the months (January=1, February=2, …, December=12).
The sequence is: 1, 1, 12, 10, X, 3, 10, Y, 9.
Observe the pattern of differences, considering a 12-month cycle:
* January (1) – 0 = January (1)
* January (1) – 1 = December (12) (1 – 1 = 0, which is month 12 in a cycle)
* December (12) – 2 = October (10)
* October (10) – 3 = July (7). So, X = July.
* July (7) – 4 = March (3)
* March (3) – 5 = October (10) (3 – 5 = -2, which is month 10 in a cycle, i.e., -2 + 12 = 10)
* October (10) – 6 = April (4). So, Y = April.
* April (4) – 7 = September (9) (4 – 7 = -3, which is month 9 in a cycle, i.e., -3 + 12 = 9)
The pattern involves subtracting consecutive integers (0, 1, 2, 3, 4, 5, 6, 7…) from the numerical value of the month, wrapping around the 12-month cycle. Thus, X is July and Y is April. This is a logical reasoning question requiring pattern identification, common in CSAT.